How to read a positive n number in ascending and hexadecimal order?

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How to read a positive n number in ascending and hexadecimal order?

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#1 by (1 votes)

-1

I have a problem with an issue and I can not resolve it. My problem is referent of how to enter these values and organizes them as the example below.

Create a program in C / C ++ reads a positive number n and prints, in   all hexadecimal numbers with n nibbles. (1   nibble = 4 bits or 1/2 byte)

Additional Restrictions:

You can not work with numbers in decimal format and convert them to hexadecimal.

The solution must adopt a vector to store the nibbles.

The solution may be recursive or not.

Example 1:

Example2:

MYCODETONOW:

#include<stdio.h>#include<stdlib.h>/*CrieumprogramaemC/C++lêumnúmeropositivoneimprime,emordemcrescente,todososnúmeroshexadecimaiscomnnibbles.(1nibble=4bitsou1⁄2byte)Restriçõesadicionais:1.Nãopodetrabalharcomnúmerosnoformatodecimaleconvertê-losparahexadecimal.3.Asoluçãodeveadotar,obrigatoriamente,umvetorparaarmazenarosnibbles.4.Asoluçãopodeserrecursivaounão.*/intmain(intargc,char*argv){unsignedshortintn=0;painel_quantidade_n(n);ordem_crescente();/*inthex=0xFF;printf("Valor inteiro: %i \n", hex);
    printf("Valor hex: %x \n", hex);
    printf("Valor hex (maiusculo): %X \n", hex);
    printf("Valor hex (4 casas): %4x \n", hex);
    printf("Valor hex (Completar com zeros): %04x \n", hex);*/

    return 0;
}

int painel_quantidade_n(int n){
    printf("DIGITE A QUANTIDADE DE NIBBLES:\n");
    scanf("%d", &n);

    if(n < 0){
        printf("OPS ... VOCE DIGITOU: (%d) NIBBLES... TENTE COM UM NUMERO POSITIVO !\n\n", n);
        n = 0;
        painel_quantidade_n(n);
    } else {
        return n;
    }
}

void ordem_crescente(){
    int nibbles[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f};
    int tam = (sizeof(nibbles) / sizeof(nibbles[0])), tmp = 0;

    for (int i=0; i<tam; i++){
        if(nibbles[i]>nibbles[i+1]){
            tmp = nibbles[i+1];
            nibbles[i+1] = nibbles[i];
            nibbles[i] = tmp;
            i = -1;
        }
    }
    printf("\n*IMPRIME ORDEM CRESCENTE*\n");
    for(int i=0; i<tam; i++){
        printf("%04X\n", nibbles[i]);
    }
}

c

asked by anonymous 26.05.2018 / 01:06

1 answer

Error "zero is not a supported scheme" PMD and checkstyle on windows 10 [closed]

score 1 · Accepted Answer

In painel_quantidade_n(int) , where painel_quantidade_n(n); is, return painel_quantidade_n(n); . Preferably, change the signature of the function to int painel_quantidade_n(void)

In ordem_crescente() , do:

void ordem_crescente(int n)
{
    int nibble[n];
    char printer[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
                       'A', 'B', 'C', 'D', 'E', 'F' };
    int i, j;
    int vaiUm = 0;
    int fim = (n > 0) ? 0 : 1;

    // Zera nibbles.
    for (i = 0; i < n; ++i)
    {
        nibble[i] = 0;
    }

    do
    {
        // Mostra o numero atual;
        for (j = n - 1; j >= 0; --j)
        {
            printf("%c", printer[nibble[j]]);
        }
        printf("\n");

        // Incrementa o nibble menos significativo, de um.
        for (j = 0, vaiUm = 0; j < n; ++j)
        {
            nibble[j] += (j == 0) ? 1 : vaiUm;

            vaiUm = nibble[j] / 16;

            if (vaiUm)
            {
                nibble[j] %= 16;
            }

            if (vaiUm && j == n - 1)
            {
                // Todos os numeros foram mostrados. Fim do programa.
                fim = 1;
            }
        }
    } while (!fim);
}