Save personal, I have the following function
exec($dia, $mes, $ano);
I would like to make a foreach to run it through an array basis. I passed as follows
$a=array("1,2,2016", "2,2,2016","3,2,2016");
foreach($a as $as){ exec($as) };
But it presents the error of the second argument onwards:
Missing argument
How can I pass these parameters?
As of PHP 5.6, you can use argument unpacking
function exec($dia, $mes, $ano){
// faz algo
}
$as = [
[1, 2, 2016],
[2, 2, 2016],
[3, 2, 2016],
];
foreach($as as $a){
exec(...$a);
};
The problem is called from the function, it must necessarily have 3 arguments, to pass they can transform this string into an array with explode() and pass each one individually.
$a = array("1,2,2016", "2,2,2016","3,2,2016");
foreach($a as $as){
$param = explode(',', $as);
exec($param[0], $param[1], $param[2]);
}
Another way to do
function nova(){
list($d, $m, $y) = explode(',', func_get_args()[0]);
echo "$d/$m/$y <br>";
}
$a=array("1,2,2016", "2,2,2016","3,2,2016");
foreach($a as $as){
nova($as);
}
Just to note, a variant of @rray's response:
$a = array(
array( '1', '2', '2016' ),
array( '2', '2', '2016' ),
array( '3', '2', '2016' )
);
foreach($a as $as){
exec( $as[0], $as[1], $as[2] );
}
As PHP is very "flexible" it even gives you the ability to do so:
$a = ["1,2,2016", "2,2,2016","3,2,2016"];
foreach($a as $as){
eval('exec('.$as.');');
}