In this code:
#include <stdio.h>
#include <stdlib.h>
struct cadastro {
char nome[50];
int idade;
char rua[50];
int numero;
};
int main()
{
struct cadastro c[4]; //Array[4] de estruturas
for(int i=0; i<4; i++) {
gets(c[i].nome);
scanf("%d", &c[i].idade);
gets(c[i].rua);
scanf("%d", &c[i].numero);
}
system("pause");
return 0;
}
How to give print on all elements of the struct, without doing it manually with a printf. For it will display four times.
To print all elements at once with a single simple statement, use 1 function!
void cadastro_print(struct cadastro *p) {
printf("nome: %s\n", p->nome);
printf("idade: %d\n", p->idade);
printf("rua: %s\n", p->rua);
printf("numero: %d\n", p->numero);
printf("\n");
}
and in main() , call this function
for (int i = 0; i < 4; i++) cadastro_print(c + i);
Hello, I think it was not clear what you wanted to ask.
First, there is no more recommended method for outputting values in C than with printf.
To print the names, just follow the same logic as you used to read them:
for (i=0;i<4;i++){
printf("%s\n",c[i].nome);
}