Suppose you have defined:
(defun xxx (x) (+ 1 x)) (setf xxx 5)
What is the value of the following expressions?
Using LISP Functional Programming, answer the exercises?
4
asked by anonymous 13.10.2017 / 01:52
1 answer
5
This defines xxx as a function that adds 1 to xxx :
(defun xxx (x) (+ 1 x))
This defines xxx as having value 5:
(setf xxx 5)
LISP maintains separate values and functions. That is, you have a xxx variable with a value of 5 and a xxx function that adds one more.
When you do this:
(print (xxx 2))
You are calling the function xxx and passing it 2 as a parameter. The result is 3.
With this:
(print (xxx (+ (xxx 5) 3)))
You are calling the function xxx and passing it 5 as a parameter, resulting in 6. Then sum 3, which gives 9. Call the function xxx again by passing 9, and gives 10. >
Already in this:
(print (+ 4 xxx))
The xxx is the number 5. Adding with 4 gives 9.
Finally, this:
(print (xxx xxx))
You call the function xxx with the value of xxx (which is 5). So this results in 6.
13.10.2017 / 02:38