Divide form to insert in different lines of the database (codeigniter)

In my view, your problem is one of logic. If your form is dynamic, there is certainly a button to add a new question, even if a previous one has not yet been saved, right?

I have had a similar problem, I had a register of people responsible for certain areas in the company, where each one has 1 name, email, phone and etc.

The problem was, how to identify the data for each person?

For this I created a JS script to organize things for me, here's how I did it:

I knew that person has name, phone and email, so we have 3 fields. I need to put the name attribute of each field so that I can identify each respective client and its data.

The structure of the fields was something like this:

<div class='contato'>
   <input type='text' name='nome' />
   <input type='text' name='email' />
   <input type='text' name='telefone' />
</div>
<!-- Saber a quantidade de grupos de campos que vamos pegar no POST -->
<input type='hidden' name='qtdCampos' id='qtdCampos' value='1' />

So my script worked like this:

function organizarCampos() {

   var i     =  0;

   var cont  =  1; 

   $( '.contato' ).find( 'input[type=text]' ).each( function () {

      //Pegando somente letras
      var name  =  $( this ).attr( 'name' ).replace(/[^a-zA-Z]+/g, '');

      //Novo valor para o name
      var newName  += i;

      $( this ).attr( 'name', newName );

      if( cont == 3 ) {
         cont = 1;
         i++;
      }else {
         cont++;
      }

   });

}

Now we need to know how many fields we'll get in POST

var qtd   =  $( '.contato' ).find( 'input[type=text]' ).length / 3;

$( '#qtdCampos' ).val( qtd );

Now in PHP

$qtdGrupos   =   $this->input->post( 'qtdCampos' );

for( $i = 0; $i < $qtdCampos; $i++ ) {
   $nome  =  $this->input->post( 'nome' . $i );
   ...
}

I hope to have helped my friend.