I need to draw 16 numbers and store them in an array, but there can be no repeated numbers. Follow the code.
var numero = [];
function numero_aleatorio () {
for(i=0;i<16;i++) {
numero.push(Math.floor((Math.random() * 16) + 1));
}
}
numero_aleatorio(); Just check if the number is in the array before adding it. It is necessary to change for by while , since it is not possible to know for sure how many iterations will be necessary to generate 16 different numbers:
var numeros = [];
function numero_aleatorio() {
while (numeros.length < 16) {
var aleatorio = Math.floor(Math.random() * 100);
if (numeros.indexOf(aleatorio) == -1)
numeros.push(aleatorio);
}
}
numero_aleatorio();
Note that Math.floor(Math.random() * 100) generates a random number between 0 and 99.
You can enter numbers from 1 to 16 within a array and use the sort method of array by randomly sorting Math.random()) ;
function _sortear(quantidade, maximo) {
var numeros = [];
console.time('Sorteando');
// Preenche um array com os números de 1 ao maximo
for (var numero = 1; numero <= maximo; numero++) {
numeros.push(numero);
}
numeros.sort(function randomizar(a, b) {
return Math.random() * 2 - 1; // Ordena randomicamente
});
console.timeEnd('Sorteando');
return numeros.splice(0, quantidade);
}
console.log(_sortear(16, 100).join(',')); Note that I created the parameters quantidade and maximo . The quantidade defines how many numbers are to be returned and maximo sets the maximum value of the random numbers.
At the end of the function I use the splice method to get the n first positions of the resulting array .
Follow the simple example friend,
public class NumerosAleatrorios{
public static void main(String[] args){
int numero;
int[] num = new int[6];
Random r = new Random();
for(int i=0; i<num.length; i++){
numero = r.nextInt(60) + 1;
for(int j=0; j<num.length; j++){
if(numero == num[j] && j != i){
numero = r.nextInt(60) + 1;
}else{
num[i] = numero;
}
}
}
//Apresentar na tela o resultado
for(int i=0; i<num.length; i++){
System.out.print(num[i]+" ");
}
}
}