How can I do a repetition a certain number of times in assembly (in the MIPS )?
Example in pseudocode, assuming that the variable registrador is a register that I want to receive all numbers from 1 to 6 (one at a time, obviously)
var i = 1;
while(i <= 6)
{
registrador = i;
i = i + 1;
}
Something like that?
.globl main
main:
li $v0, 0 # registrador
li $t0, 1 # valor inicial do índice do laço
loop:
bgt $t0, 5, exit # se $t0 > 5, interrompa laço
move $v0, $t0 # registrador = $t0
addiu $t0, $t0, 1 # incrementa índice
j loop # vá para o label [loop:]
exit:
I made a slightly simpler version of the other answer. Without using move - I changed my mind shortly after.
main:
li $t0, 0 # $t0 é o incrementador (o "i" da pergunta)
li $t1, 6 # $t1 é o valor máximo (serão 5 loops)
loop:
beq $t0, $t1, done # se o $t0 for igual a $t1, vai para 'done' (acabou o loop)
addi $t0, $t0, 1 # incrementar $t0 em 1
j loop # pular para (goto) 'while'
done:
program simq1; uses crt; var i, k: integer; vet: array [1..10] of integer;
begin clrscr; writeln ('Which are the 10 numbers?'); for i: = 1 to 10 of begin readln (vet [i]); end; for i: = 1 to 10 of begin for k: = 1 to 10 of begin if (i