Retrieve link generated by an ajax

0

Good morning guys.

I'm doing a send of data to the other domain, using, ajax + php. But I need to make this generated link open, so they can send the site data, because of the captcha.

    $.ajax({
        url:    "webproxy.php?url=" + encodeURIComponent("http://ecoprintq.com/index.php/partnerApplication/create"),

    data:            "User_full_name:aaaaaaa&User_institution:sssss",

    crossDomain:true,
    type: "GET",
    timeout: 30000,
    dataType: "text", // "xml", "json"
    success: function(data) {


    },
    error: function(jqXHR, textStatus, ex) {
        alert(textStatus + "," + ex + "," + jqXHR.responseText);
    }
});

This ajax returns:

jquery-1.10.2.js:7 XHR finished loading: GET "http://127.0.0.1/ecoLicenseLayout/webproxy.php?url=http%3A%2F%2Fecoprintq.c…FpartnerApplication%2Fcreate&User_full_name:aaaaaaa&User_institution:sssss".
send 
@ jquery-1.10.2.js:7ajax
 jquery-1.10.2.js:7(anonymous function) 
@ teste.php:44

I wanted to know if you have any function to get the

" link ... FpartnerApplication% 2Fcreate & User_full_name: aaaaaaa & User_institution: sssss "

    
asked by anonymous 12.12.2016 / 12:34

0 answers